A 0.0663 kg ingot of metal is heated to 241◦C and then is dropped into a beaker containing 0.395 kg of water initially at 25◦C.<

Question

A 0.0663 kg ingot of metal is heated to 241◦C
and then is dropped into a beaker containing
0.395 kg of water initially at 25◦C.
If the final equilibrium state of the mixed
system is 27.4
◦C, find the specific heat of
the metal. The specific heat of water is
4186 J/kg ·
◦ C.
Answer in units of J/kg ·
◦ C

in progress 0
Nguyệt Ánh 7 days 2021-07-22T14:46:41+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-22T14:48:14+00:00

    Answer:280.216j/kg°C

    Explanation:

    Mass of metal=0.0663kg

    mass of water=0.395kg

    Final temperature=27.4°C

    Temperature of metal=241°C

    Temperature of water=25°C

    specific heat capacity of water=4186j/kg°C

    0.0663xax(241-27.4)=0.395x4186x(27.4-25)

    0.0663xax213.6=0.395x4186x2.4

    14.16168a=3968.328

    a=3968.328 ➗ 14.16168

    a=280.216j/kg°C

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )