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## A 0.0125 kg bullet strikes a 0.240 kg block attached to a fixed horizontal spring whose spring constant is 2.25*10^3N/m and sets it into osc

Question

A 0.0125 kg bullet strikes a 0.240 kg block attached to a fixed horizontal spring whose spring constant is 2.25*10^3N/m and sets it into oscillation with amplitude of 12.4 cm. What was the initial speed of the bullet if the two objects move together after impact?

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Physics
6 months
2021-07-29T16:04:57+00:00
2021-07-29T16:04:57+00:00 1 Answers
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## Answers ( )

Answer:The value is

Explanation:From the question we are told that

The mass of bullet is

The mass of the block is

The spring constant is

The amplitude is

Generally according to the conservation of momentum is

given that the block was at rest we have that

Now the angular velocity of the both bodies is mathematically represented as

Given that the system after collision set into oscillation

The maximum linear velocity of the system after impact is mathematically represented as

From above equation

=>

=>