9. A 227 kg object is moved a distance of 2.4 m forward by a force. If 686 J of work is done on the object, what is the object’s acceleratio

9. A 227 kg object is moved a distance of 2.4 m forward by a force. If 686 J of work is done on the object, what is the object’s acceleration?

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  1. 1.259ms^2

    Explanation:

    since, WORK DONE = FORCE*DISTANCE

    AND, FORCE=MASS*ACCELERATION

    SO, THE WORK DONE BECOMES=MASS*ACCELERATION*DISTANCE

    ACCELERATION=WORK/(MASS*DISTANCE)

    AND, WORK=686J

    MASS=227kg

    DISTANCE=2.4m

    THEREFORE, ACCELERATION=686/(227*2.4)

    =686/544.8

    =1.259ms^2

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