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8). How many moles of oxygen gas must be placed in a 35.0 L container in order to exert a pressure of 2.80 atmospheres at 15.0°C?
Question
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Answers ( )
Answer:
4.1 moles
Explanation:
Applying
PV = nRT……………. equation 1
Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = Temperature.
make n the subject of the equation
n = PV/RT………….. Equation 2
From the question,
Given: V = 35 L , P = 2.8 atm, T = 15 °C = (15+273) = 288 K, R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (35×2.8)/(0.083×288)
n = 4.1 moles