8). How many moles of oxygen gas must be placed in a 35.0 L container in order to exert a pressure of 2.80 atmospheres at 15.0°C?

Question

8). How many moles of oxygen gas must be placed in a 35.0 L container in order
to exert a pressure of 2.80 atmospheres at 15.0°C?

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Hải Đăng 6 months 2021-08-13T09:54:55+00:00 1 Answers 3 views 0

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    2021-08-13T09:56:32+00:00

    Answer:

    4.1 moles

    Explanation:

    Applying

    PV = nRT……………. equation 1

    Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = Temperature.

    make n the subject  of the equation

    n = PV/RT………….. Equation 2

    From the question,

    Given: V = 35 L , P = 2.8 atm, T = 15 °C  = (15+273) = 288 K, R = 0.083 L.atm/K.mol

    Substitute these values into equation 2

    n = (35×2.8)/(0.083×288)

    n = 4.1 moles

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