7. Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages now.

Question

7. Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages
now.

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Hồng Cúc 4 years 2021-07-30T10:12:47+00:00 1 Answers 22 views 0

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    2021-07-30T10:14:37+00:00

    Answer: Sue is 20 and Jennifer is 26

    Step-by-step explanation:

    Let’s say that J=Jennifer’s age now and S=Sue’s age now.

    We know that:

    J=S+6

    Because Jennifer is 6 years older than Sue.

    We also know that when Jennifer is 4 years older (J+4), she will be twice as old as Sue was 5 years from now (S-5).

    So we get the following equation from that information:

    J+4=2(S-5)

    So we have the two equations:

    J+4=2(S-5)

    J=S+6

    Let’s substitute J=S+6 into the first equation (note that RHS means Right Hand Sie and LHS means Left Hand Side):

    (S+6)+4=2(S-5)

    S+10=2S-10 [Add 6+4 on the RHS, and distribute on the LHS]

    S=2S-20 [Subtract 10 from both sides]

    -S=-20 [Subtract 2S from both sides]

    S=20 [Divide both sides by -1]

    So we know S, which is Sue’s age, is 20. So Sue is no 20 years old.

    Finding Jennifer’s age now is simple. We know Jennifer is 6 years older than Sue, and Sue is 20, so Jennifer is 26 years old.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )