7: A 2 mA current passes through a 1.4 cm long solenoid producing a magnetic field of .162 G. How many turns are in the solenoid

Question

7: A 2 mA current passes through a 1.4 cm long solenoid producing a magnetic field of .162 G. How many turns are in the solenoid

in progress 0
Diễm Thu 1 year 2021-08-03T10:24:23+00:00 1 Answers 8 views 0

Answers ( )

    0
    2021-08-03T10:26:11+00:00

    Answer:

    The number of turns is 64449395

    Explanation:

    The expression for the solenoid formula is stated below, and it is what we are going to use to solve for the number of turns

    B= μ₀nl

    where B= magnetic field

               μ₀= permeability , 4π × 10⁻⁷ Henry

               n= number of turns

                l= length of coil

    Given data

    current I=  2 mA

    length L= 1.4 cm to meter we have 0.014

    magnetic field B= 0.162 T

    From the expression we can make n subject of formula we have

    n=B/μ₀l

    Substituting we have

    n= 0.162/4π × 10⁻⁷*2*10^-3

    n= 0.162/8π × 10^⁻10

    n= 0.162/2.5136*10^-9          

    n= 64449395

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )