6x – y =4 and y = 4x + 2. Solve the system and find x – 2y

0 thoughts on “6x – y =4 and y = 4x + 2. Solve the system and find x – 2y”

1. Answer:

   [tex]Point Form:(1,2)\\Equation Form:x=1,y=2[/tex]

   Step-by-step explanation:

   Let’s solve your system by substitution.

   [tex]6x-y=4;y=4x+2x-2y[/tex]

   Step: Solve 6x−y=4for y:

   [tex]6x-y=46x-y+-6x=4+-6x[/tex]

   [tex]-y=-6x+4[/tex]

   [tex]\frac{-y}{-1} =\frac{-6x+4}{-1}[/tex]

   [tex]y=6x-4[/tex]

   Step: Substitute 6x−4 for y in y=6x−2y:

   [tex]y=6x-2y\\6x-4=6x-2(6x-4)[/tex]

   [tex]6x-4=-6x+8[/tex]

   [tex]6x-4+6x=-6x+8+6x\\12x-4=8\\12x-4+4=8+4[/tex]

   [tex]12x=12\\\frac{12x}{12} =\frac{12}{12}[/tex]

   Step: Substitute 1 for x in y=6x−4:

   [tex]y=6-4\\y=(6)(1)-4\\y=2[/tex]

   Answer:

   [tex]x=1 , y=2[/tex]

   Hope this helps 🙂

   -ilovejiminssi♡

   Reply

2. Answer:

   x = 3

   x – 2y = -25

   Step-by-step explanation:

   Since y = 4x + 2 put (4x + 2) into the first equation in place of y:

   6x – (4x + 2) = 4

   To get rid of the parenthesis change 4x to -4x and 2 to -2:

   6x – 4x – 2 = 4

   If you combine the x’s you will now have only 2x

   2x – 2 = 4

   To get x by itself we add 2 to both sides

   2x = 6

   Divide by 2 on both sides:

   x = 3

   _______________________________

   For the last equation (x – 2y) we put (4x + 2) in place of y again:

   x – 2[4x + 2]

   We know the value of x already:

   3 – 2[4(3) + 2]

   Now solve for the things in parenthesis:

   3 – 2(14)

   3 – 28

   Subtract to get the answer:

   -25

   Reply