6. What is the bulk modulus of oxygen if 32.0 g of oxygen occupies 22.4 L and the speed of sound in the oxygen is 317 m/s?

Question

6. What is the bulk modulus of oxygen if 32.0 g of oxygen occupies 22.4 L and the speed of sound in the oxygen is 317 m/s?

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Yến Oanh 5 months 2021-08-09T15:58:49+00:00 1 Answers 16 views 0

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    2021-08-09T16:00:37+00:00

    Answer:

     \boxed{\sf Bulk \ modulus \ of \ oxygen \approx 143.5 \ kPa}

    Given:

    Mass of oxygen (m) = 32.0 g = 0.032 kg

    Volume occupied by oxygen (V) = 22.4 L = 0.0224 m³

    Speed of sound in oxygen (v) = 317 m/s

    To Find:

    Bulk modulus of oxygen

    Explanation:

    \sf Density \ of \ oxygen \ (\rho) = \frac{m}{V}

    \sf \implies Bulk \ modulus \ of \ oxygen \ (B) = v^{2} \rho

    \sf \implies B = v^{2}  \times\frac{m}{V}

    \sf \implies B  =  {(317)}^{2}  \times  \frac{0.032}{0.0224}

    \sf \implies B  =  {(317)}^{2}  \times 1.428

    \sf \implies B  = 100489 \times 1.428

    \sf \implies B  = 143498.292 \: Pa

    \sf \implies B   \approx 143.5 \: kPa

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