6) Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead. Kaya slows her car from 14.0 m/s to 5.5 m/s in 6.0 s. Wh

Question

6) Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead. Kaya slows her car from 14.0 m/s to 5.5 m/s in 6.0 s. What is her acceleration?

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Thu Thảo 5 months 2021-08-15T13:24:52+00:00 1 Answers 269 views 0

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    2021-08-15T13:26:51+00:00

    Answer:

    The acceleration of Kaya is 1.41\ m/s^2.

    Explanation:

    Given that,

    Initial speed of Kaya, u = 14 m/s

    Final speed of Kaya, v = 5.5 m/s

    Time, t = 6 s

    We need to find Kaya’s acceleration. We know that it is given by the change in speed per unit time. Its formula is given by :

    a=\dfrac{v-u}{t}\\\\a=\dfrac{14\ m/s-5.5\ m/s}{6\ s}\\\\a=1.41\ m/s^2

    So, the acceleration of Kaya is 1.41\ m/s^2. Hence, this is the required solution.

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