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## 6. A frustrated physics student blew up her Physics textbook using a small amount of explosive. It broke into three pieces, which miraculous

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6. A frustrated physics student blew up her Physics textbook using a small amount of explosive. It broke into three pieces, which miraculously flew off in directions that were all in the same plane. A 0.200 kg piece flew off at 20.0 m/s and a 0.100 kg piece went off at 90° to the first piece, at 30.0 m/s. a) What was the momentum of the third piece? b) If the mass of the third piece was 0.150 kg, what was its velocity right after the explosion?

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Physics
5 months
2021-08-03T00:54:07+00:00
2021-08-03T00:54:07+00:00 1 Answers
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## Answers ( )

Answer:a) p₃ = 5 kg*m/s

b) v₃ = 33.33 m/s

Explanation:Given

m₁ = 0.200 kg

v₁= 20.0 m/sim₂ = 0.100 kg

v₂= 30.0 m/sjm₃ = 0.150 kg

a) Using the equation p = m*v

p₃ = ?

If

p₁= m₁*v₁and

p₂= m₂*v₂v = 0 m/s(speed of the the Physics textbook before the explosion)

m = mass of the Physics textbook before the explosion

We apply the following Principle

m*v = p₁ + p₂ + p₃then

m*m₁*m₂*

0=v₁+v₂+p₃⇒ 0= (0.200 kg)*(20.0 m/si)j) +p₃⇒ 0= 4 kg*m/si+ 3 kg*m/sj+p₃⇒ p₃=i– 3 kg*m/sj (i)and its module is

b) Using equation

(i):p₃=i– 3 kg*m/sj⇒m₃*v₃= –i– 3 kg*m/sj⇒(0.150 kg)*v₃= –i– 3 kg*m/sj⇒ v₃= (-i– (3 kg*m/s/(0.150 kg))j⇒ v₃= – 26.67 m/si– 20 m/sjand its module is