500mL of He at 98 kPa expands to 750 mL. Find P2

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500mL of He at 98 kPa expands to 750 mL. Find P2

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Amity 2 months 2021-08-03T16:20:25+00:00 1 Answers 5 views 0

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    2021-08-03T16:22:17+00:00

    The value of P₂ is 65.33 kPa

    Explanation:

    Given:

    Volume, V₁ = 500mL

    Pressure, P₁ = 98 kPa

    Volume, V₂ = 750 mL

    Pressure, P₂ = ?

    According to Boyle’s law:

    P₁V₁ = P₂V₂

    On substituting the value we get:

    98 X 500 = 750 X P_2\\\\P_2 = \frac{98 X 500}{750} \\\\P_2 = 65.33 kPa

    The value of P₂ is 65.33 kPa

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