## 5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there is no excite

Question

5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there is no excited state absorption (  calculate a) the fractional loss per pass and b) the decay time of the cavity

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5 months 2021-08-24T04:02:17+00:00 1 Answers 2 views 0

the fractional loss per pass =0.053

the decay time of the cavity =11 ns

Explanation:

laser is an acronym for Light Amplification by Stimulated Emission of Radiation and it has lot of military applications : basically ranging from target acquisition, fire control, and training. It is also being used  in LIDAR communications, radar systems , laser guided landing systems, laser pointers, holography, photography, guidance systems, scanning machines, metal working,  and medicine.

the fractional loss per pass=

but no excited state absorption, therefore is 0

=0.053

b) the decay time of the cavity:

=1.1 *10^-8 seconds

=11 ns