5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there is no excite

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5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there is no excited state absorption (  calculate a) the fractional loss per pass and b) the decay time of the cavity

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Thu Nguyệt 5 months 2021-08-24T04:02:17+00:00 1 Answers 2 views 0

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    2021-08-24T04:04:09+00:00

    Answer:

    the fractional loss per pass =0.053

    the decay time of the cavity =11 ns

    Explanation:

    laser is an acronym for Light Amplification by Stimulated Emission of Radiation and it has lot of military applications : basically ranging from target acquisition, fire control, and training. It is also being used  in LIDAR communications, radar systems , laser guided landing systems, laser pointers, holography, photography, guidance systems, scanning machines, metal working,  and medicine.

    the fractional loss per pass= \alpha l - ln(R_1R_2)^ \frac {1}{2}

    but no excited state absorption, therefore \alpha is 0

    = - ln(R_1R_2)^ \frac {1}{2}\\\\=- ln(0.999* 0.9)^ \frac {1}{2}

    =0.053

    b) the decay time of the cavity:

    T_c = \frac{nd}{cl_f}=\frac{1,76 * 10 *10^-2}{3 *10^8 *0.53}

    =1.1 *10^-8 seconds

    =11 ns

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