5.Imagine you are ice skating with your BFF. Both of you at rest, when you shove him/her away from you. You have a mass of 65 kg and he/sh

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5.Imagine you are ice skating with your BFF. Both of you at rest, when you shove him/her away from you. You have a mass of 65 kg and he/she has a mass of 55kg. When you shove off, you move away with a velocity of 2.0 m/s. With what velocity does your BFF move away from you

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Mít Mít 3 months 2021-08-12T23:35:02+00:00 2 Answers 9 views 0

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    0
    2021-08-12T23:36:34+00:00

    Answer:

    v2 = 2.36m/s

    Explanation:

    This problem involves the concept of conservation of momentum. The principle states that total momentum before must equal the total momentum after.

    Initially total momentu was zero because both were at rest.

    Let m1 and m2 represent the masses 65kg and 55kg and let v1 = -2.0m/s and let v1 = velocity of bff

    0 = m1v1 + m2v2

    0 = 65×(-2.0) + 55v2

    55v2 = 65×2

    v2 = 65×2/55 = 130/55 = 2.36m/s

    v2 = 2.36m/s

    0
    2021-08-12T23:36:47+00:00

    Answer:

    v2 = 2.36 m/s

    Explanation:

    Momentum is simply the the product of mass of an object and it velocity. Generally, when object moves they have momentum . The unit for momentum is kgm/s.

    During collision momentum is conserved . This means that

    initial momentum = final momentum

    If their is an equal and opposite reaction your momentum should be equal to your BFF.

    m1 v1 = m2 v2

    m1 = 65 kg

    v1 = 2.0 m/s

    m2 = 55 kg

    v2 = ?

    m1 v1 = m2 v2

    65 × 2 = 55v2

    130  = 55 v2

    divide both sides by 55

    v2 = 130/55

    v2 = 2.36363636364

    v2 = 2.36 m/s

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )