(x+5)^3-3=-67 11-(2x-3)^2=2

Đáp án:

$(x + 5)³ – 3 = – 67$

$⇔ (x + 5)³ = – 67 + 3$

$⇔ (x + 5)³ = – 64$

$⇔ (x + 5)³ = ( – 4)³$

$⇔ x + 5 = – 4$

$⇔ x = – 9$

$11 – (2x – 3)² = 2$

$⇔ (2x – 3)² = 11 – 2$

$⇔ (2x – 3)² = 9$

$⇔$ \(\left[ \begin{array}{l}(2x-3)²=3²\\(2x-3)² = (-3)²\end{array} \right.\) 

$⇔$ \(\left[ \begin{array}{l}2x-3=3\\2x-3=-3\end{array} \right.\) 

$⇔$ \(\left[ \begin{array}{l}x=3\\x=0\end{array} \right.\)