## -5(3x – 2)= – 50. Im trippin over this problem bruh

Question

-5(3x – 2)= – 50. Im trippin over this problem bruh

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5 months 2021-08-17T10:57:59+00:00 2 Answers 1 views 0

1. don’t trip just use the distributive property. -5(3x-2)= -50 which would end up being -15x -7 = -50; then add 7 to both -7 which then they will cancel out and add 7 to -50 which equal -43 so x = -43

x = 4

Step-by-step explanation:

Okay so for this equation we have this:

-5(3x – 2)= – 50

because the 3x and -2 are in a parentheses that shows we have to multiply -5 we do like this:

(3x(-5) – 2(-5)) = -50

-15x + 10 = -50

Since we want to get rid of the 10 we are going to subtract 10 from both sides:

-15x + 10 = -50

– 10    -10

Since we are actually going to add -10 to -50 its going to look more like this:

-15x = -60

Now we are going to divide -15 from -15x and -60 in order to segregate -15 from x:

-15x/-15 = -60/-15

x = 4

Now we double check our work by placing 4 where x once was:

-5(3(4) – 2)= – 50

-5(12 – 2) = -50

-60 + 10 = -50

-50 = -50

Hope this helps