4a.) A 0.50 kg water balloon is thrown against a wall at 32 m/s coming to a stop. What was its change in momentum?

Question

4a.) A 0.50 kg water balloon is thrown against a wall at 32 m/s coming to a stop. What was its change in
momentum?

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Thành Đạt 4 years 2021-08-22T20:29:47+00:00 1 Answers 18 views 0

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  1. thachthao
    0
    2021-08-22T20:31:30+00:00
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    Answer:

    -16 kg m/s

    Explanation:

    Momentum is a vector quantity indicating the “amount of motion” in an object.

    The change in momentum of an object is given by:

    \Delta p = m(v-u)

    where:

    m is the mass of the object

    u is its initial velocity

    v is its final velocity

    For the water balloon in this problem, we have:

    m = 0.50 kg is the mass

    u = 32 m/s is the initial velocity

    v = 0 m/s (since the balloon comes to a stop)

    Therefore, the change in momentum is:

    \Delta p=(0.50)(0-32)=-16 kg m/s

    And the negative sign indicates that the direction is opposite to the initial velocity.

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