4. There are 1.9 moles of Oxygen gas at a pressure of 3.50 atm, and the temperature is 65°C. What is the volume of the gas? Remember t

Question

4. There are 1.9 moles of Oxygen gas at a pressure of 3.50 atm, and the temperature is 65°C. What is the
volume of the gas? Remember that R = 0.0821 L x atm/Kx mol AND that you must convert °C to K.
Fill in the variables chart:

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Thiên Hương 2 months 2021-07-29T13:28:14+00:00 1 Answers 2 views 0

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    2021-07-29T13:29:45+00:00

    Answer:

    15.06 L

    Explanation:

    Using the ideal gas law equation:

    PV = nRT

    Where;

    P = pressure (atm)

    V = volume (L)

    n = number of moles (mol)

    R = gas law constant (0.0821 Latm/molK)

    T = temperature (K)

    According to the information provided in this question,

    P = 3.50 atm

    n = 1.9 moles

    V = ?

    T = 65°C = 65 + 273 = 338K

    Using PV = nRT

    V = nRT/P

    V = (1.9 × 0.0821 × 338) ÷ (3.5)

    V = 52.725 ÷ 3.5

    V = 15.06 L

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