4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the eq

Question

4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the equation for it? Thank you!)​

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Helga 4 years 2021-07-21T20:08:03+00:00 1 Answers 5 views 0

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  1. Neala
    0
    2021-07-21T20:09:36+00:00
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    Answer:

    h = 18.65 m

    Explanation:

    Given that,

    The mass of a boulder, m = 268 kg

    The potential energy at the hill, E = 50,000 J

    We need to find the height of the hill.

    We know that, the potential energy of an object is given by :

    E = mgh

    Where

    h is the height of the hill

    So,

    h=\dfrac{E}{mg}\\\\h=\dfrac{50000}{268\times 10}\\\\h=18.65\ m

    So, the height of the hill is 18.65 m.

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