4. A 1300 kg car makes a turn with a 45 m radius. Coefficient of static friction between car tires and the road is 0.28. At which spee

Question

4. A 1300 kg car makes a turn with a 45 m radius. Coefficient of static
friction between car tires and the road is 0.28. At which speed will
the car start skidding?

in progress 0
Thông Đạt 5 months 2021-08-30T14:11:59+00:00 1 Answers 0 views 0

Answers ( )

  1. thugiang
    0
    2021-08-30T14:13:53+00:00
    Reply

    Answer: v = 11 m/s

    Explanation:

    If we ASSUME that the road is horizontal, not banked

    The maximum friction force available is μmg

    This will need to supply all of the required centripetal force

    mv²/R = μmg

    v = √(μgR) = √(0.28(9.8)(45)) = 11.1121…≈ 11 m/s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )