4. A 1300 kg car makes a turn with a 45 m radius. Coefficient of static friction between car tires and the road is 0.28. At which spee

Question

4. A 1300 kg car makes a turn with a 45 m radius. Coefficient of static friction between car tires and the road is 0.28. At which spee

Question

4. A 1300 kg car makes a turn with a 45 m radius. Coefficient of static
friction between car tires and the road is 0.28. At which speed will
the car start skidding?

in progress 0

Physics Thông Đạt 1 year 2021-08-30T14:11:59+00:00 2021-08-30T14:11:59+00:00 1 Answers 2 views 0

Answers ( )

thugiang · Answer 1 · 2021-08-30T14:13:53+00:00

thugiang

0

2021-08-30T14:13:53+00:00 August 30, 2021 at 2:13 pm

Reply

Answer: v = 11 m/s

Explanation:

If we ASSUME that the road is horizontal, not banked

The maximum friction force available is μmg

This will need to supply all of the required centripetal force

mv²/R = μmg

v = √(μgR) = √(0.28(9.8)(45)) = 11.1121…≈ 11 m/s