3 — Solve (y+4) 2 = 2 where y is a real number. Simplify your answer as much as poss

Question

3

Solve (y+4) 2 = 2 where y is a real number.
Simplify your answer as much as possible.

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Jezebel 1 year 2021-09-04T22:40:41+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-04T22:42:31+00:00

    i believe the answer is y= -3

    0
    2021-09-04T22:42:34+00:00

    Answer:

    Step-by-step explanation:

    Did you mean  (y+4)^2 = 2?  ” ^ ” denotes exponentiation.

    Expanding (y+4)^2 = 2, we get y^2 + 8y + 16 = 2, or

    y^2 + 8y + 14 = 0

    Let’s apply the quadratic formula.  First, find the discriminant, b^2 – 4ac:

    8^2 – 4(1)(14) = 64 – 56 = 8 (which is the square of 2√2).

    Because the discriminant is positive, there are two real, unequal roots (solutions).  They are:

          -8 ± √8

    x = ————– = -4 ± √2

               2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )