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3. A Japanese bullet train slows from a speed of 50 m/sec to a speed of 40 m/sec in 500m. What is its acceleration?
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Answers ( )
Answer:
-0.9 m/s²
Explanation:
Given:
Δx = 500 m
v₀ = 50 m/s
v = 40 m/s
Find: a
v² = v₀² + 2aΔx
(40 m/s)² = (50 m/s)² + 2a (500 m)
a = -0.9 m/s²