3. A 5 gm/100 ml solution of drug X is stored in a closed test tube at 25°C. If the rate of degradation of the drug is 0.05 day-1,

Question

3. A 5 gm/100 ml solution of drug X is stored in a closed test tube
at 25°C. If the rate of degradation of the drug is 0.05 day-1,
calculate the time required for the initial concentration to
drop to (a) 50% (half-life) and (b) 90% (shelf-life) of its initial
value.

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Phúc Điền 6 months 2021-07-27T15:21:07+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-27T15:22:43+00:00

    Answer:

    See explanation

    Explanation:

    The degradation of the drug is a first order process;

    Hence;

    ln[A] = ln[A]o – kt

    Where;

    ln[A] = final concentration of the drug

    ln[A]o= initial concentration of the drug = 5 gm/100

    k= degradation constant = 0.05 day-1

    t= time taken

    When [A] =[ A]o – 0.5[A]o = 0.5[A]o

    ln2.5 = ln5 – 0.05t

    ln2.5- ln5 = – 0.05t

    t= ln2.5- ln5/-0.05

    t= 0.9162 – 1.6094/-0.05

    t= 14 days

    b) when [A] = [A]o – 0.9[A]o = 0.1[A]o

    ln0.5 = ln5 -0.05t

    t= ln0.5 – ln5/0.05

    t= -0.693 – 1.6094/-0.05

    t= 46 days

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