3) A 100m track is marked off in meters. When a sprinter leaves the starting line, timers are started. The sprinter passes the 12m [E] mar

Question

3) A 100m track is marked off in meters. When a sprinter leaves the starting line, timers are started. The sprinter passes the 12m [E] mark at 1.8s and passes the 56m [E] mark at 6.7s. What was the sprinter’s velocity between those two positions?

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Hưng Khoa 4 years 2021-07-27T23:56:18+00:00 1 Answers 47 views 0

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    2021-07-27T23:57:24+00:00

    Answer:

    Explanation:

    A track 100m

    The sprinter passes 12m mark in 1.8seconds

    Let this be the initial point

    d1 = 12m

    t1 = 1.8seconds

    And Passes the 56m mark in 6.7 seconds

    Then, the second point is

    d2 = 56m

    t2 = 6.7 seconds

    The sprinter velocity between this two position

    Velocity is the rate of change of displacement

    V = displacement / time taken

    V = ∆x / ∆t

    V = (x2 – x1) / (t2 – t1)

    V = (56 – 12) / (6.7 – 1.8)

    V = 44 / 4.9

    V = 8.98 m/s

    Then, the sprinter velocity between this two position is 8.98 m/s

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