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3) A 100m track is marked off in meters. When a sprinter leaves the starting line, timers are started. The sprinter passes the 12m [E] mar
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3) A 100m track is marked off in meters. When a sprinter leaves the starting line, timers are started. The sprinter passes the 12m [E] mark at 1.8s and passes the 56m [E] mark at 6.7s. What was the sprinter’s velocity between those two positions?
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Physics
4 years
2021-07-27T23:56:18+00:00
2021-07-27T23:56:18+00:00 1 Answers
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Answer:
Explanation:
A track 100m
The sprinter passes 12m mark in 1.8seconds
Let this be the initial point
d1 = 12m
t1 = 1.8seconds
And Passes the 56m mark in 6.7 seconds
Then, the second point is
d2 = 56m
t2 = 6.7 seconds
The sprinter velocity between this two position
Velocity is the rate of change of displacement
V = displacement / time taken
V = ∆x / ∆t
V = (x2 – x1) / (t2 – t1)
V = (56 – 12) / (6.7 – 1.8)
V = 44 / 4.9
V = 8.98 m/s
Then, the sprinter velocity between this two position is 8.98 m/s