3.(x-1/2)-3.(x-1/3) =x
`3(x-1/2)-3(x-1/3)=x`
`⇒3x-3/2-3x+1=x`
`⇒x=-3/2+1`
`⇒x=-1/2`
Vậy `x=-1/2`.
`3(x – 1/2) – 3.(x – 1/3) = x`
`<=> 3x – 3/2 – 3x + 1 = x`
`<=> x = -1/2`
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`3(x-1/2)-3(x-1/3)=x`
`⇒3x-3/2-3x+1=x`
`⇒x=-3/2+1`
`⇒x=-1/2`
Vậy `x=-1/2`.
`3(x – 1/2) – 3.(x – 1/3) = x`
`<=> 3x – 3/2 – 3x + 1 = x`
`<=> x = -1/2`