3.00 L of a gas is collected at 150 K and then allowed to expand to 15.0 L. What must the new temperature be in degrees C in order to<

3.00 L of a gas is collected at 150 K and then allowed to expand to
15.0 L. What must the new temperature be in degrees C in order to
maintain the same pressure (as required by Charles’ Law)?

0 thoughts on “3.00 L of a gas is collected at 150 K and then allowed to expand to 15.0 L. What must the new temperature be in degrees C in order to<”

  1. Answer:

    477 ºC

    Explanation:

    on an isobaric process, an increase on the volume implies an increase on the temperature:

    V1/T1 = V2/T2

    T2 = V2T1/V1 = 15.0 L×150 K/3.00 L = 750 K

    t/ºC = T/K – 273 = 750 K/K – 273

    t = 477 ºC

    V1: initial volume

    T1: initial temperature

    V2: final volume

    T2: final temperature

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