3.00 L of a gas is collected at 150 K and then allowed to expand to
15.0 L. What must the new temperature be in degrees C in order to
maintain the same pressure (as required by Charles’ Law)?
3.00 L of a gas is collected at 150 K and then allowed to expand to
15.0 L. What must the new temperature be in degrees C in order to
maintain the same pressure (as required by Charles’ Law)?
Answer:
477 ºC
Explanation:
on an isobaric process, an increase on the volume implies an increase on the temperature:
V1/T1 = V2/T2
T2 = V2T1/V1 = 15.0 L×150 K/3.00 L = 750 K
t/ºC = T/K – 273 = 750 K/K – 273
t = 477 ºC
V1: initial volume
T1: initial temperature
V2: final volume
T2: final temperature