2Al + 6HCl → 2AlCl3 + 3H2 If 12 moles of Al completely react, how many moles of H2 are produced?

Question

2Al + 6HCl → 2AlCl3 + 3H2

If 12 moles of Al completely react, how many moles of H2 are produced?

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Nem 7 months 2021-07-26T22:39:15+00:00 1 Answers 3 views 0

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    2021-07-26T22:40:32+00:00

    Answer:

    18 moles of H₂.

    Explanation:

    The balanced equation for the reaction is given below:

    2Al + 6HCl –> 2AlCl₃ + 3H₂

    From the balanced equation above,

    2 moles of Al reacted to produce 3 moles of H₂.

    Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:

    From the balanced equation above,

    2 moles of Al reacted to produce 3 moles of H₂.

    Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.

    Thus, 18 moles of H₂ were obtained from the reaction.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )