$27x^3-27x^2+18x-4$ $=27(x^3-x^2+\dfrac{2}{3}x-\dfrac{4}{27})$ $=27(x-\dfrac{1}{3})(x^2-\dfrac{2}{3}x+\dfrac{4}{9})$ Reply
$27x^3-27x^2+18x-4$
$=27(x^3-x^2+\dfrac{2}{3}x-\dfrac{4}{27})$
$=27(x-\dfrac{1}{3})(x^2-\dfrac{2}{3}x+\dfrac{4}{9})$