22. Glycerol, C3H8O3, is a substance used extensively in the manufacture of cosmetics, foodstuffs, antifreeze, and plastics. Glycerol is a w

Question

22. Glycerol, C3H8O3, is a substance used extensively in the manufacture of cosmetics, foodstuffs, antifreeze, and plastics. Glycerol is a water-soluble liquid with a density of 1.2656 g/mL at 15 0C. Calculate the molarity of a solution of glycerol made by dissolving 50.000 mL glycerol at 15 0C in enough water to make 250.00 mL of solution. Show work.

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Hải Đăng 4 years 2021-07-13T10:02:00+00:00 1 Answers 251 views 0

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  1. Latifah
    0
    2021-07-13T10:03:12+00:00
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    Answer:

    2.75M

    Explanation:

    Density = mass/volume

    Density of glycerol (C3H8O3) at 15°C is given as 1.2656 g/mL.

    Volume of glycerol at this same temperature before dissolving in water = 50mL

    Hence, using Density = mass/volume

    1.2656 = mass/50

    mass = 1.2656g/mL × 50mL

    mass = 63.28g

    Molarity of solution = number of moles (n) ÷ volume (V)

    Volume of glycerol dissolved in water = 250mL = 0.250L

    number of moles = mass/molar mass

    Molar mass of C3H8O3 = 12(3) + 1(8) + 16(3)

    = 36 + 8 + 48

    = 44 + 48

    = 92g/mol

    n = 63.28g ÷ 92g/mol

    n = 0.688mol

    * Molarity = n/V

    Molarity = 0.688/0.250

    Molarity = 2.75M

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