2.What is the slope-intercept form of a line that contains the points (5, – 5) and has a slope of -3? 3. Write an equation of a

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2.What is the slope-intercept form of a line that contains the points (5, – 5) and has a slope of -3?

3. Write an equation of a line that is parallel to y = – 5/2 x + 3 but travels through the origin? (Note: Parallel lines have the same slope.)

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Sigridomena 2 weeks 2021-07-16T06:58:03+00:00 1 Answers 1 views 0

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    2021-07-16T06:59:56+00:00

    Answer:

    2. y – (-5) = -3 (x – 5)

    3. y = -5/2

    Step-by-step explanation:

    Point intercept form: y – y₁ = m (x – x₁)

    Where y and x are just kept as y and x, y₁ and x₁ are the parts of a coordinate, and m = slope.

    2. The points are (5, -5) and the slope is -3. Plug this into y – y₁ = m (x – x₁) to get

    y – (-5) = -3 (x – 5)

    3. As stated, parallel lines have the same slope, so the slope of the line would be -5/2. The origin is (0, 0), so plug these two numbers in.

    y – y₁ = m (x – x₁)

    y – 0 = -5/2 (x – 0)

    y = -5/2

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