2 m3 of an ideal gas are compressed from 100 kPa to 200 kPa. As a result of the process, the internal energy of the gas increases by 10 kJ,

Question

2 m3 of an ideal gas are compressed from 100 kPa to 200 kPa. As a result of the process, the internal energy of the gas increases by 10 kJ, and 150 kJ of heat is transferred to the surroundings. How much work was done by the gas during the process?

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King 3 weeks 2021-08-22T19:11:13+00:00 1 Answers 0 views 0

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    2021-08-22T19:12:17+00:00

    Answer:

    work done is -150 kJ

    Explanation:

    given data

    volume v1 = 2 m³

    pressure p1 = 100 kPa

    pressure p2 = 200 kPa

    internal energy = 10 kJ

    heat is transferred  = 150 kJ

    solution

    we know from 1st law of thermodynamic is

    Q = du +W    …………1

    put here value and we get

    -140 = 10 + W

    W = -150 kJ

    as here work done is -ve so we can say work is being done on system

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