2) A sprig with a length of 15 cm and stores 110 J of potential energy when stretched to a new length If the sprig constant is 3

Question

2) A sprig with a length of 15 cm and stores 110 J of potential energy when stretched to a new
length
If the sprig constant is 350 N/m. Find the new length of that spring

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Phúc Điền 3 years 2021-07-30T13:40:59+00:00 1 Answers 6 views 0

Answers ( )

    0
    2021-07-30T13:42:52+00:00

    Answer:

    94.28 cm

    Explanation:

    The formula for elastic potential energy is given as;

    PEel = 1/2 *k*x² where x is the displacement, k is the spring constant

    Given

    PEel = 110 J, k= 350 N/m  then find x

    PEel = 1/2 *k*x²

    110 = 1/2 * 350 * x²

    110 = 175 x²

    110/175 = x²

    0.6286=x²

    √0.6286 =x

    0.7928 m = x

    79.28 cm = x

    New length of spring = 15 cm + 79.28 cm = 94.28 cm

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