(X+2)(X+3)(X+4)=990 I know that x=7 but how do i solve it without substitution? ie. i don’t want to use y=x+3 where

Question

(X+2)(X+3)(X+4)=990

I know that x=7 but how do i solve it without substitution?

ie. i don’t want to use y=x+3 where 990=(y-1)(y)(y+1)

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Mít Mít 5 months 2021-08-18T17:00:08+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-08-18T17:02:01+00:00

    Step-by-step explanation:

    foctorized 990 = 9×10×11

    so, (X+2)(X+3)(X+4)=9×10×11

    we can choose one of the factors, and get the answer with the same x values

    x+2 = 9 , => x =7

    x+3 = 10, => x = 7

    x+4 = 11, => x = 7

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