( x+2) (x+3) (x+4) (x+5) -24 giúp mình vs ạk

( x+2) (x+3) (x+4) (x+5) -24
giúp mình vs ạk

0 thoughts on “( x+2) (x+3) (x+4) (x+5) -24 giúp mình vs ạk”

  1. Đáp án:

    (x + 2)(x + 3)(x + 4)(x + 5) – 24 = (x + 1)(x + 6)(x^2 + 7x + 16) 

    Giải thích các bước giải:

    (x + 2)(x + 3)(x + 4)(x + 5) – 24

    = (x + 2)(x + 5)(x + 3)(x + 4) – 24

    = (x^2 + 7x + 10)(x^2 + 7x + 12) – 24

    Đặt x^2 + 7x + 11 = t

    => (t + 1)(t – 1) – 24  = t^2 – 1 – 24

    = t^2 – 25

    = t^2 – 5^2 = (t – 5)(t + 5)

    = (x^2 + 7x + 11 – 5)(x^2 + 7x + 11 + 5)

    = (x^2 + 7x + 6)(x^2 + 7x + 16)

    = (x^2 + x + 6x + 6)(x^2 + 7x + 16)

    = [x(x + 1) + 6(x + 1)](x^2 + 7x + 16)

    = (x + 1)(x + 6)(x^2 + 7x + 16)

    Reply
  2. `(x+2)(x+3)(x+4)(x+5)-24`

    `=[(x+2)(x+5)][(x+2)(x+3)]`

    `=(x^2+7x+10)(x^2+7x+12)-24`

    `=(x^2+7x+11-1)(x^2+7x+12+1)-24`

    `=(x^2+7x+11)^2-1-24`

    `=(x^2+7x+11)-5^2`

    `=(x^2+7x+11-5)(x^2+7x+11-5)`

    `=(x^2+7x+6)(x^2+7x+16)`

     

    Reply

Leave a Comment