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Acacia
Acacia

Acacia

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Acacia
Asked: Tháng Mười 17, 20202020-10-17T17:25:05+00:00 2020-10-17T17:25:05+00:00In: Môn Toán

2x ^2 – 2xy – 5x + 5y; b) 8x^2 + 4xy – 2ax – ay; c) x^3 – 4x^2 + 4x; d) 2xy – x^2 – y^2 + 16

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2x ^2 – 2xy – 5x + 5y; b) 8x^2 + 4xy – 2ax – ay;
c) x^3 – 4x^2 + 4x; d) 2xy – x^2 – y^2 + 16;
e) x^2 – y^2 – 2yz – z^2; g) 3a^2 – 6ab + 3b^2 – 12c^2.
giải chi tiết giúp mk vs ạ
đừng chép mạng
thank you

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    1. Khải Quang

      Khải Quang

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      quangkhai
      2020-10-17T17:26:35+00:00Added an answer on Tháng Mười 17, 2020 at 5:26 chiều

      Đáp án:

       

      Giải thích các bước giải:

      a) 2x2−2xy−5x+5y2×2−2xy−5x+5y

      =y(5−2x)−x(5−2x)

      =(5−2x)(y−x).

      b) 8x2+4xy−2ax−ay

      =2x(4x−a)+y(4x−a)

      c) x3−4x2+4x

      =x(x2−4x+4)

      =x(x−2)2

      d) 2xy−x2−y2+162xy−x2−y2+16

      =(x2−2xy+y2−42)

      e) x2−y2−2yz−z2

      =x2−(y2+2yz+z2)

      =x2−(y+z)2

      =(x−y+z)(x+y+z)

      g) 3a2−6ab+3b2−12c2

      =3(a2−2ab+b2−4c2)

      =3[(a−b)2−(2c)2]

      =−(x2−2xy+y2−42)=−(x2−2xy+y2−42)

      =−[(x−y)2−42]=−[(x−y)2−42]

      =−(x−y−4)(x−y+4)

      =x²-(y+z)²=(x-y-z)=(x+y+z)

      bn học tốt nhá<3

       

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    2. Dulcie

      Dulcie

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      Dulcie
      2020-10-17T17:26:53+00:00Added an answer on Tháng Mười 17, 2020 at 5:26 chiều

      Đáp án:

       

      Giải thích các bước giải: 

      A) 2x^2 – 2xy – 5x + 5y 

      = ( 2x^2 – 2xy ) – ( 5x + 5y ) 

      = 2y – xy 

      B) 8x^2 + 4xy -2ax -ay

      = 64x + 4xy – 2ax  –  ay 

      = ( 64x + 4xy ) – ( 2ax + ay ) 

      = 68x^2y – 2xy

      = 68^2 

      C) x^ 3 – 4x^2 + 4x

      = ( x^3 – 4x^2 ) + 4x 

      = 4x + 4x 

      = 16x^2

      D) 2xy – x^2 – y^2 + 16;

      = 2xy – x^2 –  y^2 + 16

      = 2xy – ( x^2 +  y^2 ) +16

      = 2xy – xy + 16

      E ) x^2 – y^2 – 2yz – z^2 

      =  x^2 – y^2 + 2yz + z^2 

      = ( x^2 – y^2 + z^2 ) + 2yz 

      = xyz + 2yz 

      G)  3a^2 – 6ab + 3b^2 – 12c^2.

      = 3a^2 – 6ab – 3b^2 + 12c^2 

      = ( 3a^2 – 3b^2 + 12c^2 ) – 6ab

      = 12abc – 6ab 

      = 6c

       

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