`(2x – 1)² = 5⁴ : 25` Trường hợp 1: `(2x – 1)² = 5⁴ : 5 ²` `(2x – 1)² = 5²` `→ (2x – 1) = 5` `→ 2x = 6` `→ x = 3` Trường hợp 2: `(2x – 1)² = – 5²` `(`Vì `- 5² = 5²)` `→ (2x – 1) = – 5` `→ 2x = – 4` `→ x = – 4 : 2` `→ x = – 2` Vậy, `x ∈ {3; – 2}` – Answered by Meett1605 Reply
$(2×x-1)^{2}$ `=`$5^{4}$ : `25` `⇒` $(2×x-1)^{2}$ `=` $5^{4}$ : $5^{2}$ `⇒` $(2×x-1)^{2}$ `=` $5^{2}$ `⇒` `2×x-1` `=` `±5` Trường hợp `1` : `2×x-1` `=` `5` `⇒` `2×x` `=` `5+1` `⇒` `2×x` `=` `6` `⇒` `x` `=` `6:2` `⇒` `x` `=` `3` Trường hợp `2` : `2×x-1` `=` `-5` `⇒` `2×x` `=` `-5+1` `⇒` `2×x` `=` `-4` `⇒` `x` `=` `-4:2` `⇒` `x` `=` `-2` Vậy `x` `∈` `{ `3` ; `-2` }` Reply
`(2x – 1)² = 5⁴ : 25`
Trường hợp 1:
`(2x – 1)² = 5⁴ : 5 ²`
`(2x – 1)² = 5²`
`→ (2x – 1) = 5`
`→ 2x = 6`
`→ x = 3`
Trường hợp 2:
`(2x – 1)² = – 5²` `(`Vì `- 5² = 5²)`
`→ (2x – 1) = – 5`
`→ 2x = – 4`
`→ x = – 4 : 2`
`→ x = – 2`
Vậy, `x ∈ {3; – 2}`
– Answered by Meett1605
$(2×x-1)^{2}$ `=`$5^{4}$ : `25`
`⇒` $(2×x-1)^{2}$ `=` $5^{4}$ : $5^{2}$
`⇒` $(2×x-1)^{2}$ `=` $5^{2}$
`⇒` `2×x-1` `=` `±5`
Trường hợp `1` :
`2×x-1` `=` `5`
`⇒` `2×x` `=` `5+1`
`⇒` `2×x` `=` `6`
`⇒` `x` `=` `6:2`
`⇒` `x` `=` `3`
Trường hợp `2` :
`2×x-1` `=` `-5`
`⇒` `2×x` `=` `-5+1`
`⇒` `2×x` `=` `-4`
`⇒` `x` `=` `-4:2`
`⇒` `x` `=` `-2`
Vậy `x` `∈` `{ `3` ; `-2` }`