|x^2 +1|-x^2+1/2.x=-3 tìm x |1/2+x^2|+|1/3+x^2|=2.(x^2-1/5+x)

|x^2 +1|-x^2+1/2.x=-3
tìm x
|1/2+x^2|+|1/3+x^2|=2.(x^2-1/5+x)

0 thoughts on “|x^2 +1|-x^2+1/2.x=-3 tìm x |1/2+x^2|+|1/3+x^2|=2.(x^2-1/5+x)”

  1. Đáp án:

    a)$x=4$
    b)$x=-\dfrac{25}{12}$

    Giải thích các bước giải:

    a) $|x^2+1|-x^2+\dfrac{1}{2}x=3$
    $⇔x^2+1-x^2+\dfrac{1}{2}x=3$
    $⇔\dfrac{1}{2}x=2$
    $⇔x=4$
    b)$|x^2+\dfrac{1}{2}|+|x^2+\dfrac{1}{3}|=2(x^2-\dfrac{1}{5}x)$
    ⇔$x^2+\dfrac{1}{2}+x^2+\dfrac{1}{3}=2x^2-\dfrac{2}{5}x$
    $⇔-\dfrac{2}{5}x=\dfrac{5}{6}$
    $⇔x=-\dfrac{25}{12}$

    Reply

Leave a Comment