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120 sweets are shared out into three piles, in the ratio 3:4:1. How many more sweets does the biggest pile have than the smalles
Question
120 sweets are shared out into three piles, in
the ratio 3:4:1. How many more sweets does
the biggest pile have than the smallest?
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Mathematics
5 months
2021-09-01T03:55:06+00:00
2021-09-01T03:55:06+00:00 1 Answers
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Answers ( )
Answer:
35
Step-by-step explanation:
3+4+1=8
120/8=15
3:4:1
45:50:15
50-15=35
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