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100 g of water are cooled and the enthalpy change is -12,540 J. What is the change in temperature of the water?
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Answers ( )
Answer:
-29.9907
Explanation:
c = Q / (mΔT)
You’re looking for ΔT, so you would plug in what you already know and get C= -12540/(100 x ΔT)
then you would solve