1. Write the equation of the line for the points (2,-1) and (-4,11).

Question

1. Write the equation of the line for the points (2,-1) and (-4,11).

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Khánh Gia 2 weeks 2021-09-02T05:51:50+00:00 1 Answers 0 views 0

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    2021-09-02T05:52:56+00:00

    Answer:

    y=-2x+3

    Step-by-step explanation:

    Slope-intercept form of an equation is written as y=mx+b, where m is the slope and b is the y-intercept.

    The slope of a line that passes through the points (x_1,\: y_1) and (x_2, \: y_2) is m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}. Using the coordinates (2, -1) and -4,11) as given in the problem, we have slope of this line to be:

    m=\frac{11-(-1)}{-4-2}=\frac{12}{-6}=-2.

    Now using this slope we’ve found and any point the line passes through, we can find the y-intercept of this equation:

    -1=-2(2)+b, \\ b=3

    Therefore, the equation of this line in slope-intercept form is \fbox{$y=-2x+3$}.

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