1) What is the value of G at 120.0 K for a reaction in which H = +35 kJ/mol and S = 1.50 kJ/(molK)?

Question

1) What is the value of G at 120.0 K for a reaction in which H = +35 kJ/mol and S = 1.50
kJ/(molK)?

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Nick 4 years 2021-08-22T09:39:23+00:00 1 Answers 52 views 0

Answers ( )

  1. Cherry
    0
    2021-08-22T09:40:39+00:00
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    Answer:

    ΔG = -145kJ/mol

    Explanation:

    To solve this question we must use the change in Gibbs free energy:

    ΔG = ΔH – TΔS

    Where ΔG is change in Gibbs free energy = ?

    ΔH is enthalpy change = +35kJ/mol

    T is absolute temperature = 120.0K

    And ΔS is change in entropy = 1.50kJ/molK

    Replacing:

    ΔG = 35kJ/mol – 120.0K*1.50kJ/molK

    ΔG = 35kJ/mol – 180kJ/mol

    ΔG = -145kJ/mol

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