1) Un cuerpo se mueve desacelerando a razón de 8m/s2, calcula: a) La velocidad que tenía 5 segundos antes de detenerse. b) La distancia reco

Question

1) Un cuerpo se mueve desacelerando a razón de 8m/s2, calcula: a) La velocidad que tenía 5 segundos antes de detenerse. b) La distancia recorrida los últimos 5 segundos de su trayectoria.

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Acacia 2 weeks 2021-07-21T22:40:59+00:00 1 Answers 0 views 0

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    2021-07-21T22:41:59+00:00

    Answer:

    Initial velocity (u) = 40 m/s

    Distance travel in last 5 seconds = 100 m

    Explanation:

    Given:

    Acceleration (a) = 8 m/s²

    Final velocity (v) = 0 m/s

    Find;

    1] Initial velocity before 5 sec

    2] Distance travel in last 5 seconds

    Computation:

    1] Initial velocity before 5 sec

    v = u + at

    0 = u + (-8)(5)

    u – 40 = 0

    Initial velocity (u) = 40 m/s

    2] Distance travel in last 5 seconds

    s = ut + (1/2)(a)(t²)

    s = (40)(5) + (1/2)(-8)(5²)

    s = 200 – 100

    Distance travel in last 5 seconds = 100 m

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