1. The octane present in gasoline burns according to the following equation: 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

Question

1. The octane present in gasoline burns according to the following equation:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

(a) How many moles of O2 are needed to react fully with 27.5 moles of octane?

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Ngọc Khuê 5 months 2021-09-01T03:49:46+00:00 1 Answers 0 views 0

Answers ( )

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    2021-09-01T03:50:51+00:00

    Answer:

    n_{O_2}=343.75molO_2

    Explanation:

    Hello there!

    In this case, according to the combustion of octane:

    2C_8H_1_8+25O_2\rightarrow 16CO_2+18H_2O

    We can see there is a 2:25 mole ratio of octane to oxygen; therefore, we can calculate the moles of oxygen via the following stoichiometric factor:

    n_{O_2}=27.5molC_8H_1_8*\frac{25molO_2}{2molC_8H_1_8} \\\\n_{O_2}=343.75molO_2

    Best regards!

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