1. Electron (-) has a charge of 1.6 x 10-19 C. Proton (+) has a charge of 1.6 x 10-19 C. In a hydrogen atom the distance between a pro

Question

1. Electron (-) has a charge of 1.6 x 10-19 C. Proton (+) has a charge of 1.6 x 10-19
C. In a hydrogen atom the distance between a proton and an electron is
5.3 x 10-12 meter.
a) Calculate the force acting between the proton and the electron. Show your
work. Remember to include a correct force unit in your final answer.

in progress 0
Bình An 1 month 2021-08-04T01:53:42+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-08-04T01:55:03+00:00

    Answer:

    8.2\cdot 10^{-6} N, attractive

    Explanation:

    The magnitude of the electrostatic force between two charges is given by Coulomb’s law:

    F=k\frac{q_1 q_2}{r^2}

    where:

    k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb’s constant

    q_1, q_2 are the two charges

    r is the separation between the two charges

    And the force is:

    – Repulsive if the two charges have same sign

    – Attractive if the two charges have opposite signs

    In this problem:

    q_1=1.6\cdot 10^{-19}C is the magnitude of the charge of the electron

    q_2=1.6\cdot 10^{-19}Cis the magnitude of the charge of the proton

    r=5.3\cdot 10^{-12} m is the separation between the two particles

    So the magnitude of the force is

    F=(8.99\cdot 10^9)\frac{(1.6\cdot 10^{-19})^2}{(5.3\cdot 10^{-12})^2}=8.2\cdot 10^{-6} N

    And since the two charges have opposite signs, the force is attractive.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )