1. A horizontal curve with a radius of 800ft connects the tangents of a two-lane highway with a design superelevation of 0.06 and a coeffici

Question

1. A horizontal curve with a radius of 800ft connects the tangents of a two-lane highway with a design superelevation of 0.06 and a coefficient of side friction of 0.14. Lanes are to be 12-feet wide and there is no median. Please calculate: a) What is the speed limit to be posted for a vehicle traversing this curve

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Nem 5 months 2021-08-14T15:53:53+00:00 2 Answers 2 views 0

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    0
    2021-08-14T15:55:16+00:00

    Answer:

    vmax=72.59m/s

    Explanation:

    To solve this problem we use

    v_{max}=\sqrt{Rg\frac{sin\alpha +f_{f}cos\alpha }{cos\alpha-f_{f}sin\alpha}}

    where R is the radius of the curve, g is the gravity constant, α is the degree of superelevation, ff is the friction coefficient. By replacing we have

    v_{max}=\sqrt{(800+6)(32.2)\frac{sin(0.06)+0.14cos(0.06)}{cos(0.06)-0.14sin(0.06)}}=72.59\frac{m}{s}

    where we have taken into account that R=800+6 due to the 12-feet of the Lanes, but we take one half, because we assume the car is at the center of the Lane.

    I hope this is useful for you

    regards

    0
    2021-08-14T15:55:51+00:00

    Answer: V = 72.05 ft/s

    Explanation: Please find the attached file for the solution

    Ignore the first file.

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