1.A hand exerciser utilizes a coiled spring. A force of 89.0 N is required to compress the spring by 0.0191 m. Determine the force needed to

Question

1.A hand exerciser utilizes a coiled spring. A force of 89.0 N is required to compress the spring by 0.0191 m. Determine the force needed to compress the spring by 0.0508 m.

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Acacia 4 years 2021-07-29T14:06:18+00:00 2 Answers 834 views -1

Answers ( )

  1. Doris
    0
    2021-07-29T14:07:25+00:00
    Reply

    Answer:

    Force needed to compress spring by 0.0508 m = 236.71 N (Approx.)

    Explanation:

    Given:

    Force applied = 89 N

    Length of spring compress = 0.0191 m

    Find:

    Force needed to compress spring by 0.0508 m

    Computation:

    Using Hooke’s law

    F = K(x)

    Constant K = F / x

    Constant K = 89 / 0.0191

    Constant K = 4,659.68 N/m

    Force needed to compress spring by 0.0508 m

    So,

    Force needed to compress spring by 0.0508 m = K(X)

    Force needed to compress spring by 0.0508 m = (4,659.68)(0.0508)

    Force needed to compress spring by 0.0508 m = 236.71 N (Approx.)

  2. Helga
    0
    2021-07-29T14:07:39+00:00
    Reply

    Answer:

    236.71 N

    Explanation:

    Applying,

    F = ke…………….. Equation 1

    Where F = force, k = spring constant, e = extension.

    make k the subject of the equation

    k = F/e………….. Equation 2

    From the question,

    Given: F = 89 N, e = 0.0191 m

    Susbtitute these values into equation 2

    k = 89/0.0191

    k = 4659.69 N/m

    When e = 0.0508 m

    The force needed is given as

    F = (4659.69×0.0508)

    F = 236.71 N

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