1- A 30 gram bullet travels at 300 m/s. How much kinetic energy does it have?

Question

1- A 30 gram bullet travels at 300 m/s. How much kinetic energy does it have?

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Lệ Thu 2 months 2021-08-22T11:25:58+00:00 2 Answers 22 views 0

Answers ( )

    0
    2021-08-22T11:27:30+00:00

    Given:

    • Mass (m) of the bullet = 30 grams
    • Velocity of the bullet (v) = 300 m/s

    To Find: Kinetic energy of the bullet.

    We know,

    E = ½mv²

    where,

    • Eₖ = Kinetic energy,
    • m = Mass &
    • v = Velocity.

    thus,

    Eₖ = ½(30 g)(300 m/s)²

    = (15 g)(90000 m²/s²)

    = 1350000 g m²/s²

    = 1350 kg m²/s²

    = 1350 J

    = 1.35 kJ (Ans.)

    0
    2021-08-22T11:27:42+00:00

    Answer:

    1.35 kJ  

    Explanation:

    KE = ½mv² = ½ × 0.030  kg × (300 m·s⁻¹)² = 1350 J = 1.35 kJ

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