1.a) x ² -10x =0 b) 8x ²-72x=0 c)x ²+9x =0

Question

1.a) x ² -10x =0
b) 8x ²-72x=0
c)x ²+9x =0

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Dâu 1 year 2020-10-20T23:28:42+00:00 2 Answers 73 views 0

Answers ( )

    0
    2020-10-20T23:30:27+00:00

    `a, x^2-10x=0`

    `<=>x.(x-10)=0`

    `<=>` \(\left[ \begin{array}{l}x=0\\x-10=0\end{array} \right.\) 

    `<=>` \(\left[ \begin{array}{l}x=0\\x=10\end{array} \right.\) 

     Vậy `x ∈ {0;10}`

    `b,8x^2-72x=0`

    `<=> 8x(x-9)=0`

    `<=>` \(\left[ \begin{array}{l}8x=0\\x-9=0\end{array} \right.\) 

    `<=>` \(\left[ \begin{array}{l}x=0\\x=9\end{array} \right.\) 

    `c,x^2+9x=0`

    `<=>x(x+9)=0`

    `<=>` \(\left[ \begin{array}{l}x=0\\x+9=0\end{array} \right.\) 

    `<=>` \(\left[ \begin{array}{l}x=0\\x=-9\end{array} \right.\) 

    xin hay nhất +5*+cảm ơn

    0
    2020-10-20T23:30:37+00:00

    Đáp án:

     

    Giải thích các bước giải:

    $a)x^2-10x=0$

    $⇔x(x-10)=0$

    \(\left[ \begin{array}{l}x=0\\x-10=0\end{array} \right.\) 

    \(\left[ \begin{array}{l}x=0\\x=10\end{array} \right.\) 

     $b)8x^2-72x=0$

     $⇔8x(x-9)=0$

    \(\left[ \begin{array}{l}8x=0\\x-9=0\end{array} \right.\) 

    \(\left[ \begin{array}{l}x=0\\x=9\end{array} \right.\) 

    $c)x^2+9x =0$

    $⇔x(x+9) =0$

    \(\left[ \begin{array}{l}x=0\\x+9=0\end{array} \right.\) 

    \(\left[ \begin{array}{l}x=0\\x=-9\end{array} \right.\) 

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