Question 1: The population of Ohio’s three largest cities are: Cleveland, 479,459; Columbus, 715,230; and Cincinnati, 367,000. The average population of Ohio’s three largest cities is:
a. 520,563
b. 620,563
c. 502,563
d. 602,563
Q2: Mr. Gorski bases each student’s grade on 4 tests. On the first 3 tests, Horace scored 84, 93, and 88. What must he score on the final test to make his average 90?
a. 85
b. 88
c. 92
d. 95
Hello there! The answer to question 1:
A. 520,563
The answer to question 2:
D. 95
To solve question one, we need to find the average of these three numbers. To do so, we add all three first:
479,459 + 715,230 + 367,000 = 1,561,689
Then, after adding, we can divide our result by three because that is how many numbers were used.
1,561,689 divided by 3 = 520,563
Therefore, the average population of Ohio’s three largest cities is 520,563.
To find the answer to question two, we can start by adding the three numbers we have:
84 + 93 + 88 = 265
Because Horace had two tests where he scored in the eighties, we know that in order to average at least a 90, Horace will need to score either a 92 or a 95. When calculating, we will find that if Horace scores a 92, he will be at an average of 89.25. That means that our only reasonable answer is 95 because we can calculate that:
84 + 93 + 88 + 95 = 360
360 divided by 4 equals 90.
Therefore, scoring a 95 on Horace’s final test will put him right on the dot for an average of 90.
Your final answer is D, or 95. Horace will need to score a 95 on his final test to average out to a 90. If you need any extra help, let me know and I will gladly assist you.