Point F is on line segment \overline{EG} EG . Given FG=8,FG=8, EF=2x+4,EF=2x+4, and EG=4x-10,EG=4x−10, determine the numerical length of \overline{EF}. EF .
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Question
Point F is on line segment \overline{EG} EG . Given FG=8,FG=8, EF=2x+4,EF=2x+4, and EG=4x-10,EG=4x−10, determine the numerical length of \overline{EF}. EF .
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Answer:
26 units
Step-by-step explanation:
If point F is on the line segment EG, then EF+FG = EG
Given
FG=8,
EF=2x+4
EG=4x−10
Substitute the given values into the formula;
2x+4+8 = 4x−10
2x+12 = 4x-10
collect like terms
2x-4x = -10-12
-2x = -22
x = 22/2
x =11
Since EF = 2x+4
EF = 2(11)+4
EF = 22+4
EF = 26
Hence the numerical length of EF is 26 units