PLS HALP

A submersible is a type of underwater vessel. Suppose a submersible starts at a depth of 40 feet below sea level, represented by –40 feet. The table shows the submersible’s change in depth from one minute to the next.

Time and Depth of Submersible

2:15 p.m. 2:16 p.m. 2:17 p.m. 2:18 p.m.

–40 feet 180 feet lower 175 feet lower 185 feet lower

Answer the questions to find the depth of the submersible after 3 minutes.

1. Write and evaluate a subtraction expression to find the depth of the submersible at 2:16 p.m.

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2. Write and evaluate a subtraction expression to find the depth of the submersible at 2:17 p.m.

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3. Write and evaluate a subtraction expression to find the depth of the submersible at 2:18 p.m.

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4. If the submersible dove straight down, what is the distance between the submersible’s starting position at 2:15 and its position at 2:18? Show your work.

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Answer:Previous questionRational numbers prior question delete your full name you accidently wrote in your question for rational numbers by pressing edit icon answered here so your edit is possible ok! Answer is -2t +7t = 5tStep-by-step explanation:question asks for addition only (4t-6t= -2t)+(8t-1t=7t)This question on page =1) At 2:16 p.m.= -180ft – 40ft = -220ft 2) At 2:17 p.m = -175ft-40ft= -115ft 3) At 2:18 p.m. = -185ft – 40ft = -225ft 4) The difference is show your work by reversal 2:18-2:15 = 3 minutes so the distance is also reversed at (-225) – (-40 )= -225 + 40 = -175Step-by-step explanation:This is minus – number minus- number = minus number counting bkwardsbut when when we subtract two minus numberwith another minus itbecomes a plus + just between the bracketssee question 4 brackets use.The work is using brackets for question 4.